Use the given functions to find all values of $$ x $$ that satisfy the inequality $$ f(x) \geq g(x) $$. $$ f(x)=5 x^{2} $$ $$ g(x)=22 x-8 $$

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Solve the equation $$ 5x^{2} \geq 22x-8 $$.
Solve the inequality by following steps:
- step0: Solve the inequality by testing the values in the interval:
  $$5x^{2}\geq 22x-8$$
- step1: Move the expression to the left side:
  $$5x^{2}-\left(22x-8ight)\geq 0$$
- step2: Remove the parentheses:
  $$5x^{2}-22x+8\geq 0$$
- step3: Rewrite the expression:
  $$5x^{2}-22x+8=0$$
- step4: Factor the expression:
  $$\left(x-4ight)\left(5x-2ight)=0$$
- step5: Separate into possible cases:
  $$\begin{align}&x-4=0\&5x-2=0\end{align}$$
- step6: Solve the equation:
  $$\begin{align}&x=4\&x=\frac{2}{5}\end{align}$$
- step7: Determine the test intervals:
  $$\begin{align}&x<\frac{2}{5}\&\frac{2}{5}4\end{align}$$
- step8: Choose a value:
  $$\begin{align}&x_{1}=-1\&x_{2}=2\&x_{3}=5\end{align}$$
- step9: Test the chosen value:
  $$\begin{align}&x<\frac{2}{5}	extrm{ }	extrm{is the solution}\&\frac{2}{5}4	extrm{ }	extrm{is the solution}\end{align}$$
- step10: Include the critical value:
  $$\begin{align}&x\leq \frac{2}{5}	extrm{ }	extrm{is the solution}\&x\geq 4	extrm{ }	extrm{is the solution}\end{align}$$
- step11: The final solution is $$x \in \left(-\infty,\frac{2}{5}ight]\cup \left[4,+\inftyight):$$
  $$x \in \left(-\infty,\frac{2}{5}ight]\cup \left[4,+\inftyight)$$
The values of $$ x $$ that satisfy the inequality $$ f(x) \geq g(x) $$ are $$ x \in (-\infty, \frac{2}{5}) \cup [4, \infty) $$.
The values of $$ x $$ that satisfy $$ f(x) \geq g(x) $$ are all real numbers less than or equal to $$ \frac{2}{5} $$ and greater than or equal to 4.

Use the given functions to find all values of that satisfy the inequality .

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