4. Tensions are 2000 N and 900 N in a belt drive. The diameter of the driver pulley is $$ 0,44 \mathrm{~m} $$ and its rotational frequency is $$ 800 \mathrm{r} / \mathrm{min} $$. Calculate: a) The effective tension. b) The torque of the driver pulley. c) The work done during one revolution. d) The output power of the pulley after 45 s .

Question

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Let's solve **Problem 4(a)** step by step.

### **Given:**
- **Tensions in the belt:**
  - **T₁ (tight side)** = 2000 N
  - **T₂ (slack side)** = 900 N

### **a) The Effective Tension**

The **effective tension (Tₑ)** in a belt drive is calculated as the difference between the tight side tension and the slack side tension. This effective tension is crucial as it is responsible for transmitting the torque from the driver to the driven pulley.

$$
T_e = T_1 - T_2
$$

Plugging in the given values:

$$
T_e = 2000\, \text{N} - 900\, \text{N} = 1100\, \text{N}
$$

### **Answer:**
a) The effective tension is $$ T_e = T_1 - T_2 = 2000\,\text{N} - 900\,\text{N} = 1100\,\text{N} $$.
a) The effective tension is 1100 N.

Tensions are 2000 N and 900 N in a belt drive. The diameter of the driver pulley is
and its rotational frequency is . Calculate:
a) The effective tension.
b) The torque of the driver pulley.
c) The work done during one revolution.
d) The output power of the pulley after 45 s .

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Solución

The Deep Dive

a) Effective Tension

b) Torque of the Driver Pulley

c) Work Done During One Revolution

d) Output Power of the Pulley After 45 s

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Tensions are 2000 N and 900 N in a belt drive. The diameter of the driver pulley is and its rotational frequency is . Calculate: a) The effective tension. b) The torque of the driver pulley. c) The work done during one revolution. d) The output power of the pulley after 45 s .