What is the test statistic? $$ x_{0}^{2}=17,717 $$ (Round to three decimal places as needed.) What is the $$ P $$-value of the tesif P-value $$ =0.007 $$ (Round to three decimal places as needed.) Based on the results, do the accidents follow a uniform distribution? A. Do not reject $$ H_{0} $$, because the calculated $$ P $$-value is less than the given $$ \alpha $$ level of significance. B. Reject $$ H_{0} $$, because the calculated $$ P $$-value is greater than the given $$ \alpha $$ level of significance. C. Reject $$ H_{0} $$, because the calculated $$ P $$-value is less than the given $$ \alpha $$ level of significance. D. Do not reject $$ H_{0} $$, because the calculated $$ P $$-value is greater than the given $$ \alpha $$ level of significance.

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To determine whether to reject or not reject the null hypothesis $$ H_0 $$, we need to compare the calculated $$ P $$-value with the significance level $$ \alpha $$.

You provided the following information:
- Test statistic: $$ x_{0}^{2} = 17.717 $$
- $$ P $$-value: $$ 0.007 $$

Assuming a common significance level of $$ \alpha = 0.05 $$ (unless specified otherwise), we can analyze the results:

1. If the $$ P $$-value is less than $$ \alpha $$ (i.e., $$ 0.007 < 0.05 $$), we reject the null hypothesis $$ H_0 $$.
2. If the $$ P $$-value is greater than $$ \alpha $$, we do not reject the null hypothesis.

Since $$ 0.007 < 0.05 $$, we reject the null hypothesis $$ H_0 $$.

Based on the options provided, the correct choice is:
**C. Reject $$ H_{0} $$, because the calculated $$ P $$-value is less than the given $$ \alpha $$ level of significance.**
The correct choice is C. Reject $$ H_{0} $$ because the $$ P $$-value is less than $$ \alpha $$.

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