Calculate the horizontal and vertical components of a 550 N force pulling upwards at an angle of $$ 40^{\circ} $$ to the मorizontal.

Question

UpStudy AI · Accepted Answer

To find the horizontal and vertical components of a **550 N** force acting at an angle of $$ 40^{\circ} $$ above the horizontal, you can use trigonometric functions:

1. **Horizontal Component ($$ F_x $$)**:
   $$
   F_x = F \cos(\theta)
   $$
   $$
   F_x = 550\, \text{N} \times \cos(40^{\circ}) \approx 550\, \text{N} \times 0.7660 \approx 421\, \text{N}
   $$

2. **Vertical Component ($$ F_y $$)**:
   $$
   F_y = F \sin(\theta)
   $$
   $$
   F_y = 550\, \text{N} \times \sin(40^{\circ}) \approx 550\, \text{N} \times 0.6428 \approx 354\, \text{N}
   $$

**Summary:**
- **Horizontal Component:** $$ \approx 420\, \text{N} $$
- **Vertical Component:** $$ \approx 350\, \text{N} $$

These values are rounded to two significant figures, consistent with the given force's precision.
The horizontal component is approximately 420 N and the vertical component is approximately 350 N.

Calculate the horizontal and vertical components of a 550 N force pulling upwards at an angle of \( 40^{\circ} \) to the मorizontal.

Solución de tutoría real

Responder

Solución

Extra Insights

preguntas relacionadas

Latest Physics Questions