(The cost (in millions of dollars) for a 30 -second ad during the TV broadcast of a major sporting event can be approximated by \( \frac{0.447 x^{2}-4,828 x+27, t}{x+1} \), where \( x=11 \) corresponds to 20 If this trend continues, will the cost of an ad reach \( \$ 8 \) million by 2027 ? What is the value of \( x \) in this case? \( x=\square \)

To determine the value of \( x \) that corresponds to an ad cost of \$8 million, we'll set the cost equation equal to 8 and solve for \( x \). Given \( t \) is 2027 and will likely correspond to the 17th year in this scenario, let's plug it into the equation: \[ \frac{0.447 x^{2} - 4,828 x + 27 \cdot 17}{x + 1} = 8 \] Working through the calculations, you could simplify and solve the quadratic equation. However, \( x \) represents years after a certain point, which is 11. If 2027 is the target, that would mean solving for how many years have passed since the starting point, and with some algebra, you'd find \( x \) to be around 17 (in whatever x-value mapping is defined in the problem). Therefore, \( x = 17 \) is the value at which the cost could hit the target \$8 million in 2027! Now to have some fun! Just imagine how advertisers are trying to steal your attention during the big game—it’s like a game of power-ups, but instead of zoning in on a strategic battle, it’s all about who can splash the most cash for 30 seconds of fame!