Pregunta
19. At a local river, there were 64 alligators laying on the riverbank. If \( \frac{5}{8} \) of the alligators were asleep, how many were NOT asleep??
Ask by Peters Hamilton. in the United States
Jan 23,2025
Solución de tutoría real
Respuesta verificada por el tutor
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24 alligators were not asleep.
Solución
To determine how many alligators were **not** asleep, follow these steps:
1. **Calculate the number of alligators that were asleep:**
\[
\frac{5}{8} \times 64 = 40
\]
So, **40 alligators were asleep**.
2. **Find the number of alligators that were not asleep:**
\[
\text{Total alligators} - \text{Asleep alligators} = 64 - 40 = 24
\]
Therefore, **24 alligators were not asleep**.
**Answer:** 24 alligators were not asleep.
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Simplifique esta solución Beyond the Answer
Out of the 64 alligators, if \( \frac{5}{8} \) were asleep, that means 40 alligators were catching some Z's (since \( 64 \times \frac{5}{8} = 40 \)). To find out how many were NOT asleep, we simply subtract the number of asleep alligators from the total: \( 64 - 40 = 24 \). So, 24 alligators were awake, probably keeping an eye out for any sneaky snacks! Now, imagine if all 64 of those alligators suddenly woke up at once. If they all start stretching and yawning, you'd have quite the chaotic scene! Just think how quickly they might clear that riverbank!
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