\( -3 x y^{2} \) when \( x=6 \) and \( y=-4 \)
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To solve for \( -3xy^{2} \) when \( x=6 \) and \( y=-4 \), simply substitute the values into the expression. Start by calculating \( y^{2} \) which is \( (-4)^{2} = 16 \). Then, substitute \( x \) and \( y^{2} \) into the expression: \[ -3 \cdot 6 \cdot 16 = -288. \] Therefore, the final answer is \( -288 \). If you're dealing with negative numbers, remember that squaring a negative will always give you a positive result, which can help avoid common mistakes! It’s also helpful to break down calculations step-by-step to minimize errors when substituting values.