Simplify \( \frac{6+\frac{8}{e^{2}}}{1+\frac{2}{c}} \)
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To simplify \( \frac{6+\frac{8}{e^{2}}}{1+\frac{2}{c}} \), we start by rewriting the expression in a more manageable form. First, combine the terms in the numerator and denominator separately. **Numerator:** \[ 6 + \frac{8}{e^{2}} = \frac{6e^{2}}{e^{2}} + \frac{8}{e^{2}} = \frac{6e^{2} + 8}{e^{2}} \] **Denominator:** \[ 1 + \frac{2}{c} = \frac{c}{c} + \frac{2}{c} = \frac{c + 2}{c} \] Now, substituting these back into the original expression gives us: \[ \frac{\frac{6e^{2} + 8}{e^{2}}}{\frac{c + 2}{c}} \] This is equivalent to multiplying by the reciprocal of the denominator: \[ = \frac{6e^{2} + 8}{e^{2}} \cdot \frac{c}{c + 2} = \frac{(6e^{2} + 8)c}{e^{2}(c + 2)} \] Thus, the simplified form of the given expression is: \[ \frac{(6e^{2} + 8)c}{e^{2}(c + 2)} \]