(9) \( 5 \frac{4}{9}+3 \frac{11}{18}= \)

To solve \( 5 \frac{4}{9} + 3 \frac{11}{18} \), first convert the mixed numbers to improper fractions. For \( 5 \frac{4}{9} \): \(5 \times 9 + 4 = 45 + 4 = 49\), so you get \( \frac{49}{9} \). For \( 3 \frac{11}{18} \): \(3 \times 18 + 11 = 54 + 11 = 65\), so you have \( \frac{65}{18} \). Next, you need a common denominator to add the fractions. The least common multiple of 9 and 18 is 18. Convert \( \frac{49}{9} \) to \( \frac{49 \times 2}{9 \times 2} = \frac{98}{18} \). Now you can add: \(\frac{98}{18} + \frac{65}{18} = \frac{98 + 65}{18} = \frac{163}{18}\). Finally, convert \( \frac{163}{18} \) back to a mixed number: \( 163 \div 18 = 9\) remainder \(1\), so the answer is \( 9 \frac{1}{18} \). Thus, \( 5 \frac{4}{9} + 3 \frac{11}{18} = 9 \frac{1}{18} \).