25. If $$ x=\frac{4}{\sqrt{7}-\sqrt{3}}, y=\frac{4}{\sqrt{7}+\sqrt{3}} $$, put $$ x $$ and $$ y $$ in the simplest form , then find the value of $$ : x^{2} y^{2} $$

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To simplify $$ x $$ and $$ y $$ and find $$ x^2 y^2 $$:

1. **Simplify $$ x $$ and $$ y $$:**

$$
x = \frac{4}{\sqrt{7} - \sqrt{3}} \cdot \frac{\sqrt{7} + \sqrt{3}}{\sqrt{7} + \sqrt{3}} = \frac{4(\sqrt{7} + \sqrt{3})}{7 - 3} = \sqrt{7} + \sqrt{3}
$$

$$
y = \frac{4}{\sqrt{7} + \sqrt{3}} \cdot \frac{\sqrt{7} - \sqrt{3}}{\sqrt{7} - \sqrt{3}} = \frac{4(\sqrt{7} - \sqrt{3})}{7 - 3} = \sqrt{7} - \sqrt{3}
$$

2. **Compute $$ xy $$:**

$$
xy = (\sqrt{7} + \sqrt{3})(\sqrt{7} - \sqrt{3}) = 7 - 3 = 4
$$

3. **Find $$ x^2 y^2 $$:**

$$
x^2 y^2 = (xy)^2 = 4^2 = 16
$$

**Answer:**  
The value of $$ x^{2} y^{2} $$ is 16.
$$ x^{2} y^{2} = 16 $$

If , put and in the simplest form
, then find the value of

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