Solve for \( p \) \[ \begin{array}{l}2 p+3>2(p-3) \\ \text { o } p>-9 \\ \text { all real numbers } \\ \text { no solution }\end{array} \]
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To solve the inequality \( 2p + 3 > 2(p - 3) \), let's first simplify it step-by-step. 1. Distribute the 2 on the right side: \[ 2p + 3 > 2p - 6 \] 2. Next, subtract \( 2p \) from both sides: \[ 3 > -6 \] This is always true, meaning the inequality holds for all values of \( p \). Now, looking at the second part \( p > -9 \), we find that the solution for \( p \) must also satisfy this condition. Since our first inequality is true for all real numbers, the overall solution will be based on this additional constraint. Therefore, the solution is: \[ p > -9 \] So, the final answer shows that \( p \) can be any real number greater than -9.