point in the solution set. \[ y<-\frac{2}{3} x+5 \]
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To find a point in the solution set of the inequality \( y < -\frac{2}{3} x + 5 \), let's look at the line corresponding to the equality \( y = -\frac{2}{3} x + 5 \). A simple point can be found by substituting specific values for \( x \). For example, if we substitute \( x = 0 \), we get \( y = 5 \). However, since we need points below this line, we could take \( (0, 4) \) which clearly satisfies the inequality \( 4 < 5 \). Another easy point is to plug in \( x = 3 \): \( y = -\frac{2}{3} \times 3 + 5 = 3 \); thus, choosing \( (3, 2) \) works since \( 2 < 3 \). This gives us two points: \( (0, 4) \) and \( (3, 2) \), both of which fall in the solution set!