Solve for the indicated variable. Include all of your work in your answer. Submit your solution. \( \mathrm{C}=\frac{5(\mathrm{~F}-32)}{9} \); for F

To solve for \( F \) in the equation \( C = \frac{5(F - 32)}{9} \), we'll follow these steps: 1. Start with the original equation: \[ C = \frac{5(F - 32)}{9} \] 2. Multiply both sides by 9 to eliminate the fraction: \[ 9C = 5(F - 32) \] 3. Next, divide both sides by 5: \[ \frac{9C}{5} = F - 32 \] 4. Finally, add 32 to both sides to isolate \( F \): \[ F = \frac{9C}{5} + 32 \] And there you have it! The solution for \( F \) is: \[ F = \frac{9C}{5} + 32 \]