Rewrite the equation by completing the square. \( x^{2}-6 x-16=0 \) \( (x+\square)^{2}=\square \)

To rewrite the equation \( x^{2} - 6x - 16 = 0 \) by completing the square, follow these steps: 1. **Move the constant term to the other side:** \[ x^{2} - 6x = 16 \] 2. **Complete the square for the quadratic expression on the left:** - Take half of the coefficient of \( x \), which is \( -6 \), resulting in \( -3 \). - Square this value: \( (-3)^2 = 9 \). - Add this square to both sides of the equation: \[ x^{2} - 6x + 9 = 16 + 9 \] 3. **Simplify both sides:** \[ (x - 3)^2 = 25 \] So, the equation rewritten by completing the square is: \[ (x - 3)^2 = 25 \]