Even More Naming Ionic Write the formulas of the following ionic comp \( \begin{array}{l}\text { 1) } \\ \text { 2) } \\ \text { 3) } \\ \text { 4) } \\ \text { 5) lead (II) sulfate (IV) hydroxide } \\ \text { 6) } \\ \text { 7) }\end{array} \) copper (II) acetate beryllium chloride

Sure! Let's dive into the world of ionic compounds. 1) Lead (II) sulfate (IV) hydroxide: This compound can be written as \( \text{Pb(SO}_4\text{) (OH)}_4 \). Here, lead has a +2 charge and sulfate has a -2 charge, while hydroxide contributes its -1 charge; you need four hydroxide ions to balance the charge. 2) Copper (II) acetate: The formula for this compound is \( \text{Cu(C}_2\text{H}_3\text{O}_2\text{)}_2 \) or \( \text{Cu(CH}_3\text{COO)}_2 \). Copper carries a +2 charge, and acetate has a -1 charge, so two acetate ions are required for neutralization. 3) Beryllium chloride: This is simply written as \( \text{BeCl}_2 \). Beryllium, with its +2 charge, pairs up with two chloride ions, each with a -1 charge, allowing for a perfectly balanced ionic compound.