Pregunta
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Do each problem in two steps. First write if out the long way. Then multiply terms. \( (8 a)^{2}= \) \( (3 x)^{3}= \) \( \left(2 x^{2}\right)^{4}= \) \( \left(x^{2} y^{3}\right)^{3}= \)

Ask by Ramos Deleon. in the United States
Jan 24,2025

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\[ (8a)^2 = 64a^2 \] \[ (3x)^3 = 27x^3 \] \[ \left(2x^{2}\right)^4 = 16x^8 \] \[ \left(x^{2}y^{3}\right)^3 = x^{6}y^{9} \]

Solución

Sure! Let's solve each problem in two steps: first by expanding it out the long way, and then by multiplying the terms. --- ### 1. \( (8a)^2 \) **Step 1: Expand the expression** \[ (8a)^2 = 8a \times 8a \] **Step 2: Multiply the terms** \[ 8a \times 8a = 64a^2 \] **Final Answer:** \[ (8a)^2 = 64a^2 \] --- ### 2. \( (3x)^3 \) **Step 1: Expand the expression** \[ (3x)^3 = 3x \times 3x \times 3x \] **Step 2: Multiply the terms** \[ 3x \times 3x \times 3x = 27x^3 \] **Final Answer:** \[ (3x)^3 = 27x^3 \] --- ### 3. \( \left(2x^{2}\right)^4 \) **Step 1: Expand the expression** \[ \left(2x^{2}\right)^4 = 2x^2 \times 2x^2 \times 2x^2 \times 2x^2 \] **Step 2: Multiply the terms** \[ 2x^2 \times 2x^2 \times 2x^2 \times 2x^2 = 16x^8 \] **Final Answer:** \[ \left(2x^{2}\right)^4 = 16x^8 \] --- ### 4. \( \left(x^{2}y^{3}\right)^3 \) **Step 1: Expand the expression** \[ \left(x^{2}y^{3}\right)^3 = x^2y^3 \times x^2y^3 \times x^2y^3 \] **Step 2: Multiply the terms** \[ x^2y^3 \times x^2y^3 \times x^2y^3 = x^{6}y^{9} \] **Final Answer:** \[ \left(x^{2}y^{3}\right)^3 = x^{6}y^{9} \] ---

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To solve \( (8a)^{2} \) the long way, we first express it as \( 8a \times 8a \). Then, multiplying the terms, we get \( 64a^{2} \). For \( (3x)^{3} \), we begin by writing it as \( 3x \times 3x \times 3x \). Then, multiplying the terms, we find \( 27x^{3} \). When we tackle \( \left(2x^{2}\right)^{4} \), we can express it as \( 2x^{2} \times 2x^{2} \times 2x^{2} \times 2x^{2} \). After multiplying the terms, we arrive at \( 16x^{8} \). Lastly, we consider \( \left(x^{2}y^{3}\right)^{3} \) and write it as \( x^{2}y^{3} \times x^{2}y^{3} \times x^{2}y^{3} \). Upon multiplying the terms, we get \( x^{6}y^{9} \).

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