Simplify this expression: \( 7(y+z) \) \( \begin{array}{ll}\text { A. } 7 y z & \text { B. } 7 y+z \\ \text { C. } 7 y+7 z & \text { D. } 7 z+y\end{array} \)

To simplify the expression \( 7(y + z) \), you can use the **distributive property** of multiplication over addition. This property states that \( a(b + c) = ab + ac \). Applying this to your expression: \[ 7(y + z) = 7 \cdot y + 7 \cdot z = 7y + 7z \] **Therefore, the simplified expression is:** **C. \( 7y + 7z \)**