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The feasible region is the area on the graph where all three inequalities \( y \geq 2x - 4 \), \( x > -3 \), and \( y < 5 \) are satisfied simultaneously. It is a trapezoidal area bounded by the lines \( y = 2x - 4 \), \( x = -3 \), and \( y = 5 \).
Solución
Certainly! Let's analyze and graph the given system of linear inequalities:
\[
\begin{cases}
y \geq 2x - 4 \\
x > -3 \\
y < 5
\end{cases}
\]
### Step 1: Graph the Boundary Lines
1. **First Inequality: \( y \geq 2x - 4 \)**
- **Boundary Line:** \( y = 2x - 4 \) (a **solid** line because the inequality is \(\geq\))
- **Slope (m):** 2
- **Y-intercept (b):** \(-4\)
2. **Second Inequality: \( x > -3 \)**
- **Boundary Line:** \( x = -3 \) (a **dashed** vertical line because the inequality is \(>\))
3. **Third Inequality: \( y < 5 \)**
- **Boundary Line:** \( y = 5 \) (a **dashed** horizontal line because the inequality is \(<\))
### Step 2: Plot Each Boundary Line
1. **Plotting \( y = 2x - 4 \):**
- Start at \( (0, -4) \) on the y-axis.
- Use the slope to find another point: from \( (0, -4) \), rise 2 units and run 1 unit to the right to reach \( (1, -2) \).
- Draw a **solid** line through these points.
2. **Plotting \( x = -3 \):**
- Draw a **dashed** vertical line crossing the x-axis at \(-3\).
3. **Plotting \( y = 5 \):**
- Draw a **dashed** horizontal line crossing the y-axis at \(5\).
### Step 3: Determine the Shaded Regions
1. **For \( y \geq 2x - 4 \):**
- Shade **above** the line \( y = 2x - 4 \).
2. **For \( x > -3 \):**
- Shade **to the right** of the line \( x = -3 \).
3. **For \( y < 5 \):**
- Shade **below** the line \( y = 5 \).
### Step 4: Identify the Feasible Region
The **feasible region** is where all shaded areas overlap. This region satisfies all three inequalities simultaneously.
### Step 5: Find Intersection Points (Vertices)
To better understand the feasible region, let's find where the boundary lines intersect:
1. **Intersection of \( y = 2x - 4 \) and \( y = 5 \):**
\[
2x - 4 = 5 \\
2x = 9 \\
x = 4.5 \\
\Rightarrow (4.5, 5)
\]
2. **Intersection of \( y = 2x - 4 \) and \( x = -3 \):**
\[
y = 2(-3) - 4 = -6 - 4 = -10 \\
\Rightarrow (-3, -10)
\]
3. **Intersection of \( y = 5 \) and \( x = -3 \):**
\[
\Rightarrow (-3, 5)
\]
### Step 6: Sketch the Graph
While I can't provide a visual plot here, here's a description to help you sketch it:
1. **Draw the axes** with appropriate scales.
2. **Plot the boundary lines**:
- Draw a solid line for \( y = 2x - 4 \).
- Draw a dashed vertical line at \( x = -3 \).
- Draw a dashed horizontal line at \( y = 5 \).
3. **Shade the regions**:
- Shade above the solid line \( y = 2x - 4 \).
- Shade to the right of the dashed line \( x = -3 \).
- Shade below the dashed line \( y = 5 \).
4. **Identify the overlapping area**, which is bounded:
- **On the left** by \( x = -3 \).
- **Below** by \( y = 2x - 4 \).
- **Above** by \( y = 5 \).
This overlapping (feasible) region represents all the points \((x, y)\) that satisfy all three inequalities simultaneously.
### Step 7: Analyze the Feasible Region
- **Boundaries:**
- The vertical boundary \( x = -3 \) limits the region to \( x > -3 \).
- The line \( y = 2x - 4 \) serves as the lower boundary.
- The horizontal line \( y = 5 \) serves as the upper boundary.
- **Vertices (Corner Points):**
- Intersection of \( y = 2x - 4 \) and \( x = -3 \): \((-3, -10)\)
- Intersection of \( y = 2x - 4 \) and \( y = 5 \): \((4.5, 5)\)
- Intersection of \( y = 5 \) and \( x = -3 \): \((-3, 5)\)
These vertices can be useful for optimization problems or further analysis within the feasible region.
### Summary
The solution to the system of inequalities is the set of all points \((x, y)\) that lie:
- **To the right** of \( x = -3 \).
- **Above** the line \( y = 2x - 4 \).
- **Below** the line \( y = 5 \).
This region is a trapezoidal area on the coordinate plane bounded by the lines mentioned above.
Revisado y aprobado por el equipo de tutoría de UpStudy
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