10. Solve for $$ x $$ in the equation: $$ \sqrt[3]{2 x+4}+5=9 $$

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To solve the equation $$ \sqrt[3]{2x + 4} + 5 = 9 $$ for $$ x $$, follow these steps:

1. **Isolate the Cube Root:**
   
   Subtract 5 from both sides of the equation to isolate the cube root term:
   $$
   \sqrt[3]{2x + 4} = 9 - 5
   $$
   $$
   \sqrt[3]{2x + 4} = 4
   $$

2. **Eliminate the Cube Root:**
   
   To remove the cube root, cube both sides of the equation:
   $$
   \left( \sqrt[3]{2x + 4} \right)^3 = 4^3
   $$
   $$
   2x + 4 = 64
   $$

3. **Solve for $$ x $$:**
   
   - Subtract 4 from both sides:
     $$
     2x = 64 - 4
     $$
     $$
     2x = 60
     $$
   
   - Divide both sides by 2:
     $$
     x = \frac{60}{2}
     $$
     $$
     x = 30
     $$

**Solution:** $$ x = 30 $$
$$ x = 30 $$

10. Solve for \( x \) in the equation: \( \sqrt[3]{2 x+4}+5=9 \)

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