Find the missing dimension. Use the scale factor \( 1 \mathrm{in}: 8 \mathrm{ft} \). \( \begin{array}{l}\text { 25. Model length: } 6 \mathrm{in} . \\ \text { 26. Model height: } \\ \begin{array}{ll}\text { Actual length: } & \text { Actual height: } 28 \mathrm{ft} .\end{array}\end{array} . . \begin{array}{l}\text { in. }\end{array} \)

To find the missing dimension, we first use the scale factor given, which indicates that \(1 \text{ in} = 8 \text{ ft}\). Since the model length is 6 inches, we can calculate the actual length: \[ \text{Actual Length} = 6 \text{ in} \times 8 \text{ ft/in} = 48 \text{ ft} \] Now, to find the model height corresponding to the actual height of 28 ft, we reverse the scale factor: \[ \text{Model Height} = \frac{28 \text{ ft}}{8 \text{ ft/in}} = 3.5 \text{ in} \] So, the model height is 3.5 inches! To put this into context, imagine building a miniature version of a skyscraper! With modeling scaled down using real dimensions, you get a fascinating glimpse into architectural design without having to deal with the full 500-foot tower—perfect for showcasing to clients or studying structural integrity on a smaller scale!