\( \frac{1}{2}\left[\begin{array}{c}{2(\frac{x+3}{5})+\frac{6x}{7}}\end{array}\right]-\frac{x}{4}=0 \)
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To solve the equation \( \frac{1}{2}\left[\begin{array}{c}{2(\frac{x+3}{5})+\frac{6x}{7}}\end{array}\right]-\frac{x}{4}=0 \), let's first simplify the expression inside the brackets. Start with: \[ 2\left(\frac{x+3}{5}\right) = \frac{2(x+3)}{5} = \frac{2x + 6}{5} \] Now, add \( \frac{6x}{7} \): \[ \frac{2x + 6}{5} + \frac{6x}{7} \] To combine these fractions, we need a common denominator. The least common multiple of 5 and 7 is 35. Convert each fraction: \[ \frac{2x + 6}{5} = \frac{7(2x + 6)}{35} = \frac{14x + 42}{35} \] \[ \frac{6x}{7} = \frac{5(6x)}{35} = \frac{30x}{35} \] Now add them: \[ \frac{14x + 42 + 30x}{35} = \frac{44x + 42}{35} \] Now substitute this back into the original equation: \[ \frac{1}{2}\left(\frac{44x + 42}{35}\right) - \frac{x}{4} = 0 \] Multiply by 2 to eliminate the fraction on the left side: \[ \frac{44x + 42}{35} - \frac{x}{2} = 0 \] Now, find a common denominator for the terms, which is 70: \[ \frac{2(44x + 42)}{70} - \frac{35x}{70} = 0 \] \[ \frac{88x + 84 - 35x}{70} = 0 \] So, simplifying gives: \[ \frac{53x + 84}{70} = 0 \] Setting the numerator equal to zero: \[ 53x + 84 = 0 \] Solving for \(x\): \[ 53x = -84 \] \[ x = -\frac{84}{53} \] Therefore, the solution is: \[ x = -\frac{84}{53} \]