6. \( \frac{3}{4}+\left(\frac{1}{4}-\frac{1}{6}\right) \)

To tackle this expression, let's simplify it step by step! First, focus on the parentheses: \( \frac{1}{4} - \frac{1}{6} \). To subtract these fractions, you need a common denominator, which for 4 and 6 is 12. Rewriting the fractions: \[ \frac{1}{4} = \frac{3}{12}, \quad \frac{1}{6} = \frac{2}{12} \] Now, subtracting these gives: \[ \frac{3}{12} - \frac{2}{12} = \frac{1}{12} \] Next, substitute this back into the original expression: \[ \frac{3}{4} + \frac{1}{12} \] Again, we need a common denominator to add these fractions. The least common denominator between 4 and 12 is 12. Rewrite \( \frac{3}{4} \): \[ \frac{3}{4} = \frac{9}{12} \] Now, combine the fractions: \[ \frac{9}{12} + \frac{1}{12} = \frac{10}{12} = \frac{5}{6} \] So, the final answer is: \[ \frac{5}{6} \]