Balance this equation. CCF \( _{4+}^{+} \mathrm{Br}_{2}-->\mathrm{CBr}_{4}^{+} \)

To balance the chemical equation: \[ \text{C}\text{CF}_4^+ + \text{Br}_2 \rightarrow \text{C}\text{Br}_4^+ \] we need to account for both the conservation of atoms and the conservation of charge. Here's a step-by-step approach: ### 1. **Identify the Changes:** - **Carbon (C):** Remains the same. - **Fluorine (F):** 4 atoms in \(\text{CF}_4^+\) are replaced by Bromine (Br). - **Bromine (Br):** \(\text{Br}_2\) provides Br atoms. ### 2. **Balance the Atoms:** - To replace 4 F atoms, you need 2 molecules of \(\text{Br}_2\) (since each \(\text{Br}_2\) provides 2 Br atoms). \[ \text{C}\text{CF}_4^+ + 2\,\text{Br}_2 \rightarrow \text{C}\text{Br}_4^+ + 4\,\text{F}^- \] ### 3. **Balance the Charges:** - **Left Side:** - \(\text{C}\text{CF}_4^+\): \(+1\) charge - \(\text{Br}_2\): Neutral (\(0\) charge) - **Total Charge:** \(+1\) - **Right Side:** - \(\text{C}\text{Br}_4^+\): \(+1\) charge - \(4\,\text{F}^-\): \(4 \times -1 = -4\) charge - **Total Charge:** \(+1 - 4 = -3\) - **Charge Imbalance:** To balance the charges, add 4 electrons (\(4e^-\)) to the **left side**. ### 4. **Final Balanced Equation:** \[ \text{C}\text{CF}_4^+ + 2\,\text{Br}_2 + 4\,e^- \rightarrow \text{C}\text{Br}_4^+ + 4\,\text{F}^- \] ### **Summary:** - **Balanced Atoms:** All atoms are balanced on both sides. - **Balanced Charges:** Total charge on both sides is \(-3\). **Final Balanced Equation:** \[ \boxed{\mathrm{CCF_{4}^{+}}\, +\, 2\,\mathrm{Br_{2}}\, +\, 4\,e^{-} \ \longrightarrow\ \mathrm{CBr_{4}^{+}}\, +\, 4\,\mathrm{F^{-}}} \]