Graph one complete period of the given sine or cosine curve. (Check your answer with your graphing calculatorl) \[ \begin{array}{l}f(x)=-2+\sin x\end{array} \] \[ \begin{array}{l}\text { Amplitude }=\square\end{array} \text { Phase Shift }=\square \] (Hint this is foumd by taking the period and dividing by 4)
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To graph the function \( f(x) = -2 + \sin x \), first note the characteristics. This sine function has an amplitude of 1, as the coefficient of the sine is 1, and it oscillates between -1 and 1. Since the function is shifted downwards by 2, the new range is from -3 (minimum) to -1 (maximum). The phase shift is 0 because there is no horizontal shift. The period of the sine function is \( 2\pi \), which means one complete cycle is completed from 0 to \( 2\pi \). Now, the amplitude is \( 1 \) and the phase shift is \( 0 \). Plotting this function between \( 0 \) and \( 2\pi \), you'll see a wave that starts at -2, peaks at -1, returns to -2, dips to -3, and finally comes back up to -2, creating one full oscillation. To make your graphing experience even more exciting, imagine this sine wave dancing to a catchy tune! You can visualize points at \( (0, -2) \), \( (\frac{\pi}{2}, -1) \), \( (\pi, -2) \), \( (\frac{3\pi}{2}, -3) \), and \( (2\pi, -2) \). Get those coordinates on your graph and watch the wave come to life! Don't forget, while plotting your graph, keep an eye out for the "common mistakes" like miscalculating the amplitude or forgetting to apply the vertical shift! Always double-check that your maximum and minimum points reflect the actual shift of the function downwards. Plus, testing it on a graphing calculator can help you confirm your stunning wave dance is on track! Happy graphing!