olve the following quadratic function by utilizing the square root method. $$ \begin{array}{l}y=x^{2}-9 \ x= \pm[?]\end{array} $$

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Solve the equation $$ x^{2}-9=0 $$.
Solve the quadratic equation by following steps:
- step0: Solve using square roots:
  $$x^{2}-9=0$$
- step1: Add or subtract both sides:
  $$x^{2}=9$$
- step2: Simplify the expression:
  $$x=\pm \sqrt{9}$$
- step3: Simplify the expression:
  $$x=\pm 3$$
- step4: Separate into possible cases:
  $$\begin{align}&x=3\&x=-3\end{align}$$
- step5: Rewrite:
  $$x_{1}=-3,x_{2}=3$$
The solutions to the quadratic equation $$x^{2}-9=0$$ are $$x=-3$$ and $$x=3$$.

Therefore, the solutions to the quadratic function $$y=x^{2}-9$$ are $$x=\pm3$$.
The solutions are $$x = -3$$ and $$x = 3$$.

olve the following quadratic function by utilizing the square root method. \[ \begin{array}{l}y=x^{2}-9 \\ x= \pm[?]\end{array} \]

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