I CAN ADPLY INTEGER ODERATIONS TO REAL-V 31. One February day, the low temperature in St. Paul, MN was \( -17^{\circ} \). Over a period of three hours, the temperature rose \( 5^{\circ} \mathrm{F} \) per hour. After three hours, what the was the temperature?

To find the temperature after three hours, you start with the initial temperature of \( -17^{\circ} \) F and add the total temperature increase. Since the temperature rises \( 5^{\circ} \) F each hour for three hours, you calculate the total increase as: \[ 3 \text{ hours} \times 5^{\circ} \text{ F/hour} = 15^{\circ} \text{ F} \] Now, add this increase to the initial temperature: \[ -17^{\circ} \text{ F} + 15^{\circ} \text{ F} = -2^{\circ} \text{ F} \] So, after three hours, the temperature in St. Paul, MN was \( -2^{\circ} \) F. That’s a chilly improvement, but still a bit frosty!