6. [-/1 Points] DETAILS MY NOTES TGEIALG6 5.4.016. Complete the solution. Evaluate \( -2 x^{2}+7 x-1 \) for \( x=-2 \) \[ \begin{array}{l}-2 x^{2}+7 x-1=-2(\square)^{2}+7(\square)-1 \\ =-2(\square)+7(\square)-1 \\ =\square+(-14)-1 \\ =\square \\ \text { SUBMIT ANSWER }\end{array} \]

To evaluate the expression \( -2x^{2} + 7x - 1 \) for \( x = -2 \), we will substitute \( -2 \) into the expression step by step. 1. **Substituting \( x = -2 \)**: \[ -2(-2)^{2} + 7(-2) - 1 \] 2. **Calculating \( (-2)^{2} \)**: \[ (-2)^{2} = 4 \] 3. **Substituting back into the expression**: \[ -2(4) + 7(-2) - 1 \] 4. **Calculating \( -2(4) \)**: \[ -2(4) = -8 \] 5. **Calculating \( 7(-2) \)**: \[ 7(-2) = -14 \] 6. **Putting it all together**: \[ -8 - 14 - 1 \] 7. **Calculating the final result**: \[ -8 - 14 = -22 \] \[ -22 - 1 = -23 \] Thus, the final answer is: \[ \boxed{-23} \]