A boat is heading towards a lighthouse, whose beacon-light is 143 feet above the water. From point \( A \), the boat's crew measures the angle of elevation to the beacon, \( 5^{\circ} \), before they draw closer. They measure the angle of elevation a second time from point \( B \) to be \( 10^{\circ} \). Find the distance from point \( A \) to point \( B \). Round your answer to the nearest tenth of a foot if necessary.
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Bonus Knowledge
To find the distance from point \( A \) to point \( B \), we can use some trigonometry! First, let's determine the distance from point \( A \) to the lighthouse. We know the height of the beacon light, which is \( h = 143 \) feet, and the angle of elevation from point \( A \) is \( 5^{\circ} \). Using the tangent function: \[ \tan(5^{\circ}) = \frac{h}{d_A} \] where \( d_A \) is the distance from point \( A \) to the lighthouse. Rearranging gives us: \[ d_A = \frac{h}{\tan(5^{\circ})} = \frac{143}{\tan(5^{\circ})} \approx \frac{143}{0.08749} \approx 1633.2 \text{ feet} \] Next, we find the distance from point \( B \) to the lighthouse using the angle of elevation from point \( B \) which is \( 10^{\circ} \): \[ \tan(10^{\circ}) = \frac{h}{d_B} \] Calculating \( d_B \): \[ d_B = \frac{h}{\tan(10^{\circ})} = \frac{143}{\tan(10^{\circ})} \approx \frac{143}{0.17633} \approx 810.4 \text{ feet} \] Now, we can find the distance from point \( A \) to point \( B \): \[ d_{AB} = d_A - d_B \approx 1633.2 - 810.4 \approx 822.8 \text{ feet} \] Thus, the distance from point \( A \) to point \( B \) is approximately \( \boxed{822.8} \) feet.