If \( \frac{4}{41} \) of all rabbits in a country are in one state and \( \frac{1}{6} \) of the rabbits are in a different state, vhat fotal fractional part of the rabbit population is in those two states? The total fractional part of the rabbit population living in the two states is (Type an integer or a simplified fraction.)
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To find the total fractional part of the rabbit population in the two states, we need to add the two fractions together: \[ \frac{4}{41} + \frac{1}{6} \] To do this, we first need to find a common denominator. The least common multiple (LCM) of 41 and 6 is 246. Now, we convert each fraction: \[ \frac{4}{41} = \frac{4 \times 6}{41 \times 6} = \frac{24}{246} \] \[ \frac{1}{6} = \frac{1 \times 41}{6 \times 41} = \frac{41}{246} \] Now we can add the two fractions: \[ \frac{24}{246} + \frac{41}{246} = \frac{24 + 41}{246} = \frac{65}{246} \] Next, we simplify the fraction \(\frac{65}{246}\). Both 65 and 246 can be divided by 13: \[ \frac{65 \div 13}{246 \div 13} = \frac{5}{18} \] So, the total fractional part of the rabbit population living in the two states is \(\frac{5}{18}\).