(ii) The diameter of a copper sphere is 6 cm . The sphere is melted and drawn into a lor wire with a uniform circular cross-section. If the length of the wire is 36 cm , calcula its curved surface area. (iii) The diameter of a sphere is 6 cm . It is melted and drawn into a wire with a diameter 0.2 cm . Calculate the wire's length.
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To calculate the curved surface area of the wire, first, we need to find the radius of the wire’s circular cross-section. With a diameter of 0.2 cm, the radius will be 0.1 cm. The formula for the curved surface area (A) of a cylinder (wire) is given by A = 2πrh, where r is the radius and h is the height (or length) of the wire. Here, the radius is 0.1 cm and the length of the wire is 36 cm. Substituting the values, we have A = 2 * π * 0.1 * 36, which simplifies to A = 7.2π cm², or approximately 22.62 cm² when calculated numerically. For the second part, to find the length of the wire, we again use the volume conservation principle. The volume of the sphere is \(V_s = \frac{4}{3}πr³\) (where r = 3 cm, as the diameter is 6 cm), which calculates to \(36π\) cm³. Now, for the wire, its volume can be expressed as \(V_w = πr²h\), where r = 0.1 cm (diameter of the wire is 0.2 cm) and h is the length of the wire we want to find. Setting the two volumes equal, we get \(36π = π(0.1)²h\). Solving for h gives us \(h = 3600\) cm. This means you can create a really long wire from that tiny sphere!