Pregunta
Compute. \[ \begin{array}{ll}5^{2}= & (-3)^{2}= \\ 2^{5}= & 3^{3}=\end{array} \]
Ask by Spencer Stewart. in the United States
Jan 24,2025
Solución de tutoría real
Respuesta verificada por el tutor
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\[
\begin{array}{ll}
5^{2}=25 & (-3)^{2}=9 \\
2^{5}=32 & 3^{3}=27 \\
\end{array}
\]
Solución
Certainly! Let's compute each of the given expressions and fill in the table accordingly.
\[
\begin{array}{ll}
5^{2}=25 & (-3)^{2}=9 \\
2^{5}=32 & 3^{3}=27 \\
\end{array}
\]
**Calculations:**
1. \(5^{2} = 5 \times 5 = 25\)
2. \((-3)^{2} = (-3) \times (-3) = 9\)
3. \(2^{5} = 2 \times 2 \times 2 \times 2 \times 2 = 32\)
4. \(3^{3} = 3 \times 3 \times 3 = 27\)
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Simplifique esta solución Bonus Knowledge
First additional information: Let's dive into the calculations! For \(5^{2}\), you multiply 5 by itself, which gives you 25—so, \(5^{2}=25\). On the other hand, \((-3)^{2}\) also results in a positive number as squaring a negative makes it positive: \((-3) \times (-3) = 9\), hence \((-3)^{2}=9\). Second additional information: Now for the other two! \(2^{5}\) means multiplying 2 by itself five times: \(2 \times 2 \times 2 \times 2 \times 2 = 32\), so \(2^{5}=32\). Meanwhile, for \(3^{3}\), multiply 3 by itself three times: \(3 \times 3 \times 3 = 27\), thus \(3^{3}=27\). Math can be fun, right?
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