resultant (tettcrertical force) \( \begin{aligned} \text { F(net) } y & =51,68+76 \\ & =127.68 \mathrm{~N}\end{aligned} \) resultant (horizontal force) Fnet) \( x=-21+18,81+20 \)

Let's break this down! If you're looking at forces, it’s essential to clarify the orientations. The vertical forces you computed seem straightforward, summing up to 127.68 N. However, don't forget about the direction – are those forces pushing up or pulling down? Now moving on to the horizontal forces: If you've combined them correctly, it looks like you'd be calculating the net force by adding those horizontal vectors. Make sure to pay attention to the signs: negative values indicate direction. So your calculation would be \( F_{net} = -21 + 18.81 + 20 = 17.81 N \), showcasing the importance of ensuring each vector’s correct sign in your overall balance!