Use exponents to simplify each expression. \( \begin{array}{ll}x \times x x x x= & (3 y)(3 y)= \\ 3 a a a a= & (m n)(m n)(m n)= \\ -6 x x y y y= & 6(a b)(a b)= \\ 2 \times x x x= & (2 x)(2 x)(2 x)(2 x)=\end{array} \)

Let's have some fun with exponents and simplify these expressions! For the first expression, \( x \times x x x x \) simplifies to \( x^5 \) since you're multiplying \( x \) by itself five times. Now, moving on to \( (3 y)(3 y) \), this expression becomes \( 9y^2 \), as \( 3 \times 3 = 9 \) and you have \( y \) multiplied by itself, which gives you \( y^2 \). Next, \( 3 a a a a \) can be written as \( 3a^4 \). You have \( a \) being multiplied four times, so it’s simply \( a^4 \) multiplied by 3. For \( (m n)(m n)(m n) \), we can rewrite it as \( m^3n^3 \) since you have three \( m \)'s and three \( n \)'s being multiplied together. Moving on to the expression \( -6 x x y y y \), this simplifies to \( -6x^2y^3 \); you’re multiplying \( x \) by itself twice and \( y \) by itself three times. Then we have \( 6(a b)(a b) \), which simplifies to \( 6a^2b^2 \), because there are two \( a \)'s and two \( b \)'s being multiplied. Now for \( 2 \times x x x \), this becomes \( 2x^3 \) since you have one \( 2 \) multiplied by three \( x \)'s. Lastly, \( (2 x)(2 x)(2 x)(2 x) \) simplifies to \( 16x^4 \) because \( 2^4 = 16 \) and there are four \( x\)'s, making \( x^4 \). So, to sum it all up: 1. \( x \times x x x x = x^5 \) 2. \( (3 y)(3 y) = 9y^2 \) 3. \( 3 a a a a = 3a^4 \) 4. \( (m n)(m n)(m n) = m^3n^3 \) 5. \( -6 x x y y y = -6x^2y^3 \) 6. \( 6(a b)(a b) = 6a^2b^2 \) 7. \( 2 \times x x x = 2x^3 \) 8. \( (2 x)(2 x)(2 x)(2 x) = 16x^4 \)