3. \( \begin{aligned} x & =2 y+7 \\ x & =y+4\end{aligned} \)
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To find the solution to this system of equations, we can use substitution or elimination. Let's substitute the second equation into the first. From the equation \( x = y + 4 \), we can substitute for \( x \) in the first equation: \[ y + 4 = 2y + 7 \] Now, isolate \( y \): \[ 4 - 7 = 2y - y \\ -3 = y \\ y = -3 \] Next, substitute \( y = -3 \) back into one of the original equations to find \( x \): \[ x = -3 + 4 = 1 \] So, the solution to the system is \( (x, y) = (1, -3) \). To ensure this solution is correct, we can plug it back into both original equations and verify that both equations hold true! Happy solving!