Tony Stark tests the limits of his power suit by flying straight upwards. He begins at rest and his net acceleration is \( 2.2 \mathrm{~m} / \mathrm{s}^{2} \) straight up until he runs out of power at 1000 m . We will ignore atmospheric drag. How long did it take him to travel that 1000 m ?
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To find the time taken for Tony Stark to travel 1000 m under constant acceleration, we can use the kinematic equation: \[ d = v_0 t + \frac{1}{2} a t^2 \] Here, \(d\) is the distance traveled (1000 m), \(v_0\) is the initial velocity (0 m/s, since he starts at rest), \(a\) is the acceleration (2.2 m/s²), and \(t\) is the time in seconds. Since \(v_0 = 0\), the equation simplifies to: \[ d = \frac{1}{2} a t^2 \] Now, substituting \(d\) and \(a\) into the equation: \[ 1000 = \frac{1}{2} (2.2) t^2 \] This can be rearranged to solve for \(t^2\): \[ 1000 = 1.1 t^2 \] \[ t^2 = \frac{1000}{1.1} \approx 909.09 \] \[ t \approx \sqrt{909.09} \approx 30.15 \text{ seconds} \] Therefore, it took Tony Stark approximately 30.15 seconds to travel 1000 m.