\( 1 \leftarrow \quad \) Simplify and express answers using positive exponents only. \( \frac{6 x^{-4} y^{-3}}{4 x^{5} y^{-5}} \) \( \frac{6 x^{-4} y^{-3}}{4 x^{5} y^{-5}}=\square \) (Use positive exponents only.)

First, let's simplify the fraction by dividing the coefficients and applying the properties of exponents. The coefficients \( \frac{6}{4} \) simplifies to \( \frac{3}{2} \). For the \( x \) terms, we apply the quotient rule \( x^{a} / x^{b} = x^{a-b} \): \( x^{-4} / x^{5} = x^{-4-5} = x^{-9} \). For the \( y \) terms, we also use the quotient rule: \( y^{-3} / y^{-5} = y^{-3-(-5)} = y^{2} \). Now combining these results, we have: \[ \frac{3}{2} x^{-9} y^{2} \] To express \( x^{-9} \) with a positive exponent, we rewrite it as \( \frac{1}{x^{9}} \). This leads to the final expression: \[ \frac{3 y^{2}}{2 x^{9}} \] So, the answer is: \(\frac{3 y^{2}}{2 x^{9}} = \square\)