ind the solution of the system of equations. \[ \begin{array}{r}-3 x+8 y=-5 \\ 6 x+2 y=-8\end{array} \]
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To solve the system of equations: 1. Start with the two equations: \[-3x + 8y = -5 \quad (1)\] \[6x + 2y = -8 \quad (2)\] 2. We can manipulate one of the equations. Let's multiply equation (1) by 2 to prepare for elimination: \[-6x + 16y = -10 \quad (3)\] 3. Now, we can add equation (2) to equation (3): \[(-6x + 16y) + (6x + 2y) = -10 - 8\] This simplifies to: \[18y = -18\] 4. Divide both sides by 18 to solve for \(y\): \[y = -1\] 5. Substitute \(y = -1\) back into equation (1) to find \(x\): \[-3x + 8(-1) = -5\] \[-3x - 8 = -5\] \[-3x = 3\] \[x = -1\] So the solution to the system of equations is: \[(x, y) = (-1, -1)\]