11. [-/4 Points] DETAILS MY NOTES HARMATHAP12 4.2.020. Solve the following linear programming problem. Restrict $$ x \geq 0 $$ and $$ y \geq 0 $$. Minimize $$ g=50 x+80 y $$ subject to the following. $$ \begin{array}{r}11 x+15 y \geq 255 \ x+3 y \geq 33\end{array} $$ $$ (x, y)=\left(\begin{array}{l}15,6\end{array}\right. $$ $$ g=\square $$

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To solve the given linear programming problem, we need to find the minimum value of the objective function $$ g = 50x + 80y $$ subject to the constraints:

$$
\begin{array}{r}
11x + 15y \geq 255 \
x + 3y \geq 33
\end{array}
$$

Given that the feasible solution is $$ (x, y) = (15, 6) $$, we can substitute these values into the objective function to find the minimum value of $$ g $$.

Substitute $$ x = 15 $$ and $$ y = 6 $$ into the objective function:

$$ g = 50(15) + 80(6) $$

Now, we can calculate the value of $$ g $$.
Calculate the value by following steps:
- step0: Calculate:
  $$50\times 15+80\times 6$$
- step1: Multiply the numbers:
  $$750+80\times 6$$
- step2: Multiply the numbers:
  $$750+480$$
- step3: Add the numbers:
  $$1230$$
The minimum value of the objective function $$ g $$ is 1230 when $$ x = 15 $$ and $$ y = 6 $$.

Therefore, $$ g = 1230 $$.
The minimum value of $$ g $$ is 1230 when $$ x = 15 $$ and $$ y = 6 $$.

[-/4 Points] DETAILS MY NOTES HARMATHAP12 4.2.020.
Solve the following linear programming problem. Restrict and .
Minimize subject to the following.

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[-/4 Points] DETAILS MY NOTES HARMATHAP12 4.2.020. Solve the following linear programming problem. Restrict and . Minimize subject to the following.