Solve each system by graphing. \( \begin{array}{l}\text { 28) } \\ y=-3 x+3 \\ y=-\frac{1}{2} x-2\end{array} \)

Solve the system of equations \( y=-3x+3;y=-\frac{1}{2}x-2 \). Solve the system of equations by following steps: - step0: Solve using the substitution method: \(\left\{ \begin{array}{l}y=-3x+3\\y=-\frac{1}{2}x-2\end{array}\right.\) - step1: Substitute the value of \(y:\) \(-3x+3=-\frac{1}{2}x-2\) - step2: Multiply both sides of the equation by LCM: \(\left(-3x+3\right)\times 2=\left(-\frac{1}{2}x-2\right)\times 2\) - step3: Calculate: \(-6x+6=\left(-\frac{1}{2}x-2\right)\times 2\) - step4: Calculate: \(-6x+6=-x-4\) - step5: Move the expression to the left side: \(-6x+x=-4-6\) - step6: Add and subtract: \(-5x=-4-6\) - step7: Add and subtract: \(-5x=-10\) - step8: Change the signs: \(5x=10\) - step9: Divide both sides: \(\frac{5x}{5}=\frac{10}{5}\) - step10: Divide the numbers: \(x=2\) - step11: Substitute the value of \(x:\) \(y=-3\times 2+3\) - step12: Simplify: \(y=-3\) - step13: Calculate: \(\left\{ \begin{array}{l}x=2\\y=-3\end{array}\right.\) - step14: Check the solution: \(\left\{ \begin{array}{l}x=2\\y=-3\end{array}\right.\) - step15: Rewrite: \(\left(x,y\right) = \left(2,-3\right)\) The solution to the system of equations \(y=-3x+3\) and \(y=-\frac{1}{2}x-2\) is \(x=2\) and \(y=-3\).