Select the best description of the following exponential equation. \( f(x)=49(0.7)^{x} \) Show your work here Hint: To add an exponent ( \( x^{v} \) ), type "exponent" or press "A" Gecaying by \( 70 \% \) with every unit of \( x \). Growing by \( 30 \% \) with every unit of \( x \). Decaying by \( 30 \% \) with every unit of \( x \).

To analyze the exponential equation \( f(x)=49(0.7)^{x} \), we need to look at the base of the exponent, which is \( 0.7 \). Since \( 0.7 \) is less than \( 1 \), this indicates that the function is decaying. The decay factor is \( 1 - 0.7 = 0.3 \), meaning it is decaying by \( 30 \% \) with every unit increase in \( x \). Therefore, the best description of the equation is: Decaying by \( 30 \% \) with every unit of \( x \). In real-world terms, this could represent a situation like the depreciation of an asset, where its value decreases over time at a steady rate. For instance, if you bought a gadget for $49, and it loses 30% of its value with each passing year, you'd quickly see how the numbers start reflecting just how much it diminishes in worth!