Simplify the algebraic expression \( \frac{x^{2}-2 x y+y^{2}}{\frac{x}{y}-\frac{y}{x}} \) \( \frac{x^{2}-2 x y+y^{2}}{\frac{x}{y}-\frac{y}{x}}=\square \)
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To simplify the algebraic expression \( \frac{x^{2}-2 x y+y^{2}}{\frac{x}{y}-\frac{y}{x}} \), let's first simplify the denominator. The denominator, \( \frac{x}{y}-\frac{y}{x} \), can be combined over a common denominator: \[ \frac{x^2 - y^2}{xy} \] Next, the expression for the numerator, \( x^{2}-2xy+y^{2} \), is a perfect square trinomial that can be factored: \[ (x - y)^2 \] Now we can rewrite the original expression: \[ \frac{(x - y)^2}{\frac{x^2 - y^2}{xy}} = (x - y)^2 \cdot \frac{xy}{x^2 - y^2} \] Notice that \( x^2 - y^2 \) can also be factored as \( (x - y)(x + y) \): \[ = (x - y)^2 \cdot \frac{xy}{(x - y)(x + y)} = \frac{(x - y)xy}{x + y} \] So the simplified expression is: \[ \frac{(x - y)xy}{x + y} \]