(4) $$ 36 p^{3} q^{4}-48 p^{4} q^{2} $$

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To factor the expression $$ 36 p^{3} q^{4} - 48 p^{4} q^{2} $$, follow these steps:

1. **Find the Greatest Common Factor (GCF):**
   - **Coefficients:** The GCF of 36 and 48 is 12.
   - **Variables $$ p $$:** The smallest power of $$ p $$ is $$ p^3 $$.
   - **Variables $$ q $$:** The smallest power of $$ q $$ is $$ q^2 $$.

So, the GCF is $$ 12 p^{3} q^{2} $$.

2. **Factor out the GCF:**
   $$
   36 p^{3} q^{4} - 48 p^{4} q^{2} = 12 p^{3} q^{2} \left( \frac{36}{12} q^{4-2} - \frac{48}{12} p^{4-3} \right)
   $$
   Simplifying inside the parentheses:
   $$
   12 p^{3} q^{2} \left( 3 q^{2} - 4 p \right)
   $$

**Final Factored Form:**
$$
12 p^{3} q^{2} (3 q^{2} - 4 p)
$$

**Answer:**
After factoring, the expression is 12 p³q² multiplied by ( 3 q² – 4 p ). Thus,

12p³q²(3q²−4p)
The factored form of the expression $$ 36 p^{3} q^{4} - 48 p^{4} q^{2} $$ is $$ 12 p^{3} q^{2} (3 q^{2} - 4 p) $$.

(4) \( 36 p^{3} q^{4}-48 p^{4} q^{2} \)

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