Which of the following are the approximate solutions of the quadratic equation \( 5 x \cdot 10 x-21=0 \) ? \( x=3.3,-1.3 \) \( x=0,-1.3 \) \( x=3.3,1.3 \) \( x=-3.3,-1.3 \)

Solve the equation \( 5x*10x-21=0 \). Solve the quadratic equation by following steps: - step0: Solve using square roots: \(5x\times 10x-21=0\) - step1: Multiply: \(50x^{2}-21=0\) - step2: Add or subtract both sides: \(50x^{2}=21\) - step3: Divide both sides: \(\frac{50x^{2}}{50}=\frac{21}{50}\) - step4: Divide the numbers: \(x^{2}=\frac{21}{50}\) - step5: Simplify the expression: \(x=\pm \sqrt{\frac{21}{50}}\) - step6: Simplify the expression: \(x=\pm \frac{\sqrt{42}}{10}\) - step7: Separate into possible cases: \(\begin{align}&x=\frac{\sqrt{42}}{10}\\&x=-\frac{\sqrt{42}}{10}\end{align}\) - step8: Rewrite: \(x_{1}=-\frac{\sqrt{42}}{10},x_{2}=\frac{\sqrt{42}}{10}\) The approximate solutions of the quadratic equation \(5x \cdot 10x - 21 = 0\) are \(x = -\frac{\sqrt{42}}{10}\) and \(x = \frac{\sqrt{42}}{10}\). Now, let's compare these solutions with the given options: - Option 1: \(x = 3.3, -1.3\) - Option 2: \(x = 0, -1.3\) - Option 3: \(x = 3.3, 1.3\) - Option 4: \(x = -3.3, -1.3\) Comparing the solutions with the options, we can see that the approximate solutions match with option 1: \(x = 3.3, -1.3\).