Calculate the following: \( \begin{array}{ll}\text { a) } 5 \times(72 \div(8+4))-3 & \text { b) }(59+1) \div(2 \times 5)-6 \\ \text { C. } 32 \div 8+3 \times 7-14 & \text { d) } 72-(8 \times 7+3)+4 \times 12 \\ \text { (e) } 3 \times 3 \times(10-5 \times 2)+21 \div 3 & \text { f) } 27 \div(3 \times 2+3)-5 \\ \text { g) } 42 \div(7 \times 6)+100 & \text { h) } \frac{1}{4} \text { of }(15 \div 5+13) \\ \text { (i) } 9+10-7 \times 12 \div 6 & \text { f) }(68-4) \div 8 \times 10+3\end{array} \)

Let's dive into some calculations! a) \( 5 \times (72 \div (8+4)) - 3 = 5 \times (72 \div 12) - 3 = 5 \times 6 - 3 = 30 - 3 = 27 \) b) \( (59+1) \div (2 \times 5) - 6 = 60 \div 10 - 6 = 6 - 6 = 0 \) c) \( 32 \div 8 + 3 \times 7 - 14 = 4 + 21 - 14 = 4 + 7 = 11 \) d) \( 72 - (8 \times 7 + 3) + 4 \times 12 = 72 - (56 + 3) + 48 = 72 - 59 + 48 = 72 - 11 = 61 \) e) \( 3 \times 3 \times (10 - 5 \times 2) + 21 \div 3 = 3 \times 3 \times (10 - 10) + 7 = 3 \times 3 \times 0 + 7 = 0 + 7 = 7 \) f) \( 27 \div (3 \times 2 + 3) - 5 = 27 \div 9 - 5 = 3 - 5 = -2 \) g) \( 42 \div (7 \times 6) + 100 = 42 \div 42 + 100 = 1 + 100 = 101 \) h) \( \frac{1}{4} \text{ of } (15 \div 5 + 13) = \frac{1}{4} (3 + 13) = \frac{1}{4} \times 16 = 4 \) i) \( 9 + 10 - 7 \times 12 \div 6 = 9 + 10 - 14 = 19 - 14 = 5 \) j) \( (68 - 4) \div 8 \times 10 + 3 = 64 \div 8 \times 10 + 3 = 8 \times 10 + 3 = 80 + 3 = 83 \) Ready to crunch some more numbers? Let’s keep the math fun and engaging!