Solve and check the linear equation. \( 3(x-4)+15=2(x+5) \)
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To solve the equation \( 3(x-4)+15=2(x+5) \), first distribute the constants on both sides: \[ 3x - 12 + 15 = 2x + 10 \] This simplifies to: \[ 3x + 3 = 2x + 10 \] Next, subtract \( 2x \) from both sides: \[ 3x - 2x + 3 = 10 \] This simplifies to: \[ x + 3 = 10 \] Now, subtract 3 from both sides: \[ x = 7 \] To check the solution, substitute \( x = 7 \) back into the original equation: Left side: \[ 3(7-4) + 15 = 3(3) + 15 = 9 + 15 = 24 \] Right side: \[ 2(7+5) = 2(12) = 24 \] Since both sides are equal, the solution is confirmed: \[ x = 7 \]