\begin{tabular}{l} Solve for \( y \). \\ \( \qquad 11.2=7 y \) \\ \( y=\square \) \\ \hline\end{tabular} \begin{tabular}{|l|l}\hline & 5 \\ \hline\end{tabular}

To solve for \( y \) in the equation \( 11.2 = 7y \), you need to isolate \( y \). Divide both sides of the equation by 7: \[ y = \frac{11.2}{7} \] Calculating this gives \( y = 1.6 \). So, the correct value to fill in the square is \( 1.6 \). Now, let's make sense of those calculations! Dividing by 7 may seem tricky at first, but it's a handy tool in algebra. When you see a number being multiplied by a variable, remember, dividing by that multiplier is your key to freedom! Just think of it as unlocking the box to find out what the variable holds inside!