(A) Use the quadratic formula to solve this equation and find the appropriate integer values of \( N, M \), and \( D \). Do not worry about simplifying the \( \sqrt{D} \) yet in this part of the problem. \[ N=13 ; D=361 \] (B) Now simplify the radical and the resulting solutions. Enter your answers as a list of integers or reduced fractions, separated with commas. Example: \( -5 / 2,-3 / 4 \) \[ t=\square \]

To solve the quadratic equation \( Ax^2 + Bx + C = 0 \) using the quadratic formula \( x = \frac{-B \pm \sqrt{D}}{2A} \), we can plug in the values \( N=13 \) and \( D=361 \). With \( A=1, B=-13, \) and \( C=0 \) (since the equation simplifies to \( x^2 - 13x = 0 \)), we first calculate \( x = \frac{13 \pm \sqrt{361}}{2} \). Now, simplifying further, we know that \( \sqrt{361} = 19 \). Thus, the solutions become \( x = \frac{13 + 19}{2} \) and \( x = \frac{13 - 19}{2} \), leading to the integer solutions \( x = 16 \) and \( x = -3 \). So the integers are: \[ t = 16, -3 \]