Determine which of the following points are included in the solution set to the following linear inequality. \[ \begin{array}{l}-3 x+4 y<20\end{array} \] Answer \( \square(-10,7) \) \( \square(0,0) \) \( \square(-1,5) \) \( \square(10,-10) \) \( \square\left(-3, \frac{11}{4}\right) \)

To determine which points satisfy the inequality \(-3x + 4y < 20\), we can substitute each point into the inequality. 1. For the point \((-10,7)\): \(-3(-10) + 4(7) = 30 + 28 = 58\) (not less than 20) → **not in the solution set.** 2. For the point \((0,0)\): \(-3(0) + 4(0) = 0\) (less than 20) → **in the solution set.** 3. For the point \((-1,5)\): \(-3(-1) + 4(5) = 3 + 20 = 23\) (not less than 20) → **not in the solution set.** 4. For the point \((10,-10)\): \(-3(10) + 4(-10) = -30 - 40 = -70\) (less than 20) → **in the solution set.** 5. For the point \(\left(-3, \frac{11}{4}\right)\): \(-3(-3) + 4\left(\frac{11}{4}\right) = 9 + 11 = 20\) (not less than 20) → **not in the solution set.** Final answers: - \(\square(-10,7)\) - \(\square(0,0)\) ✓ - \(\square(-1,5)\) - \(\square(10,-10)\) ✓ - \(\square\left(-3, \frac{11}{4}\right)\)