22.5: GCE JUNE 2017. PI 1. Evaluate \( \frac{5}{8} \div \frac{5}{4}-\frac{3}{4} \times 1 \frac{1}{3} \) gives A: \( \frac{1}{2} \) B: \( -\frac{1}{2} \) C. \( \frac{25}{32} \) D: \( -\frac{7}{32} \) 2. The value of the digit 5 in 0.0513 is: A: 5 units B: 5 hundreds C: 5 tens D: 5 hundredths 3. The product \( y^{a} \cdot y^{2 a} \) simplifies to A: \( (2 y)^{3 a} \) B: \( y^{3 a} \) C: \( y^{3 a^{2}} \) D: \( y^{4^{a}} \) 4. At town P , the temperature is \( -10^{\circ} \mathrm{C} \). At town Q , the temperature is \( 30^{\circ} \mathrm{C} \). the increase in temperature betw sen downs ? and Q is: A: \( 40^{\circ} \mathrm{C} \) B: \( 20^{\circ} \mathrm{C} \) C: \( -40^{\circ} \mathrm{C} \) D: \( -20^{\circ} \mathrm{C} \) 5. \( \sqrt{45} \) simplifies to: A: 15 3: \( 5 \sqrt{3} \) C: \( 9 \sqrt{5} \) D: \( 3-\sqrt{5} \) 6. 0.08 converted to a fras tirr is A: \( \frac{4}{5} \) B. \( \frac{2}{25} \) C: \( \frac{8}{25} \) D: \( \frac{4}{25} \)
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The Deep Dive
Let's dive into the fun and fascinating world of mathematics! When you're dividing fractions, remember to multiply by the reciprocal! So for \( \frac{5}{8} \div \frac{5}{4} \), flip \( \frac{5}{4} \) to get \( \frac{4}{5} \) and multiply. This will help you simplify complex fraction problems like a pro! Now, speaking of digits, the value of 5 in 0.0513 is all about its position. Since it's two places to the right of the decimal point, it represents 5 hundredths! Position matters, and understanding place values helps with everything from basic math to complex financial calculations.