Question
upstudy study bank question image url

\begin{tabular}{l} (iv) From the graph, estimate the co-ordinates of the local maximum point and the local \\ minimum point of \( g(x) \), as accurately as possible. \\ Local maximum point: \\ Local minimum point: \\ different function, \( h(x) \), has the following equation: \\ Find \( h^{\prime}(x) \), the derivative of \( h(x) \) \\ \( h^{\prime}(x)=x^{3}+2 x^{2}-x-8 \) \\ \hline (x) \end{tabular}

Ask by Medina Lawson. in Ireland
Jan 20,2025

Real Tutor Solution

Tutor-Verified Answer

Answer

To estimate the local maximum and minimum points of \( g(x) \), analyze the graph to find the highest and lowest points, then note their coordinates. For \( h(x) \), the derivative \( h^{\prime}(x) \) is already given as \( x^{3} + 2x^{2} - x - 8 \).

Solution

It looks like you're working on a multi-part problem involving functions \( g(x) \) and \( h(x) \). I'll address each part based on the information provided: --- ### (iv) Estimating Local Maximum and Minimum Points of \( g(x) \) **Task:** From the graph, estimate the coordinates of the local maximum and minimum points of \( g(x) \). **Answer:** To accurately estimate the coordinates of the local maximum and minimum points of \( g(x) \), you would need to analyze the graph of the function. Here's how you can approach it: 1. **Identify Peaks and Troughs:** - **Local Maximum:** Look for the highest point (peak) in a specific interval. - **Local Minimum:** Look for the lowest point (trough) in a specific interval. 2. **Estimate Coordinates:** - **Local Maximum Point:** Determine the \( x \)-value where the peak occurs and read the corresponding \( y \)-value. - **Local Minimum Point:** Determine the \( x \)-value where the trough occurs and read the corresponding \( y \)-value. **Example Format:** - **Local maximum point:** \( (x_{\text{max}}, y_{\text{max}}) \) - **Local minimum point:** \( (x_{\text{min}}, y_{\text{min}}) \) *Since the graph isn't provided here, you'll need to apply this method using your specific graph to find the estimated coordinates.* --- ### Finding the Derivative \( h^{\prime}(x) \) of \( h(x) \) **Given:** You mentioned that for a different function \( h(x) \), the derivative is provided as: \[ h^{\prime}(x) = x^{3} + 2x^{2} - x - 8 \] **Task:** Find \( h^{\prime}(x) \), the derivative of \( h(x) \). **Answer:** If \( h^{\prime}(x) = x^{3} + 2x^{2} - x - 8 \) is provided, it implies that the derivative has already been calculated. However, if you're looking to verify or understand how to find the derivative, here's a step-by-step guide assuming you have the original function \( h(x) \): 1. **Original Function \( h(x) \):** Suppose \( h(x) \) is a polynomial function. For example: \[ h(x) = \frac{1}{4}x^{4} + \frac{2}{3}x^{3} - \frac{1}{2}x^{2} - 8x + C \] *(Note: The constant \( C \) represents the integration constant and would disappear upon differentiation.)* 2. **Differentiation Rules Applied:** - **Power Rule:** \(\frac{d}{dx} [x^n] = n \cdot x^{n-1}\) - **Constant Multiple Rule:** \(\frac{d}{dx} [k \cdot f(x)] = k \cdot f^{\prime}(x)\) - **Sum Rule:** \(\frac{d}{dx} [f(x) + g(x)] = f^{\prime}(x) + g^{\prime}(x)\) 3. **Applying to \( h(x) \):** \[ h^{\prime}(x) = \frac{d}{dx} \left( \frac{1}{4}x^{4} \right) + \frac{d}{dx} \left( \frac{2}{3}x^{3} \right) - \frac{d}{dx} \left( \frac{1}{2}x^{2} \right) - \frac{d}{dx} (8x) + \frac{d}{dx} (C) \] \[ h^{\prime}(x) = x^{3} + 2x^{2} - x - 8 \] This confirms the provided derivative. **Conclusion:** If you have the original function \( h(x) \), you can apply these differentiation rules to find \( h^{\prime}(x) \). Since \( h^{\prime}(x) \) is already given as \( x^{3} + 2x^{2} - x - 8 \), it appears the derivative has been correctly determined. --- If you need further assistance with specific parts of the problem or have additional information (like the equation for \( h(x) \) or the graph of \( g(x) \)), feel free to provide more details!

Reviewed and approved by the UpStudy tutoring team

error msg
Explain
Simplify this solution

Extra Insights

The local maximum point, based on a standard graph shape, is typically where the function peaks before descending. For \( g(x) \), let's estimate this point at coordinates \( (a, b) \). The local minimum point occurs in the valley where the function dips before rising again, so you might find it around \( (c, d) \). Without the specific graph, let’s say the local maximum could be \( (2, 5) \) and the local minimum around \( (-1, -2) \). Now, regarding the derivative \( h^{\prime}(x) = x^{3} + 2x^{2} - x - 8 \), it gives insight into the behavior of the function. To find where the function has its critical points (local max, min), you can set this derivative to zero and solve for \( x \). This helps in identifying potential turning points, so you can plan your next steps and determine the nature of these points with second derivative tests or a sign chart.

Try Premium now!
Try Premium and ask Thoth AI unlimited math questions now!
Maybe later Go Premium
Study can be a real struggle
Why not UpStudy it?
Select your plan below
Premium

You can enjoy

Start now
  • Step-by-step explanations
  • 24/7 expert live tutors
  • Unlimited number of questions
  • No interruptions
  • Full access to Answer and Solution
  • Full Access to PDF Chat, UpStudy Chat, Browsing Chat
Basic

Totally free but limited

  • Limited Solution
Welcome to UpStudy!
Please sign in to continue the Thoth AI Chat journey
Continue with Email
Or continue with
By clicking “Sign in”, you agree to our Terms of Use & Privacy Policy